replace a string containing " with sed

nab_elf · 12-01-2015, 08:31 AM

Hello,
could you please tell me how to use sed in the purpose of replacing a string containing " with an other string , exaple:

my string is "@id": "45002"

i would like to delete all occurence of " and @ and id , finally the output is : 45002

thank's
regards

berndbausch · 12-01-2015, 09:29 AM

A string containing " is expressed as

Code:

.*".*

but I doubt this is what you want.

Can you be more specific? Do you want to remove all occurrences of " @ i d?

grail · 12-01-2015, 01:41 PM

You might think of looking at it from 2 different points:

1. What you want to get rid (current method)

2. What you want to keep (ie search for the number in the line)

Often if you get stuck looking at it from only one point of view you may miss an easier alternative

RockDoctor · 12-01-2015, 03:23 PM

Something like this?

Code:

# echo '"@id": "45002"' | sed -e 's/["@]//g'  
id: 45002

chrism01 · 12-01-2015, 05:58 PM

Code:

echo '"@id": "45002"'|sed -e 's/["a-z@]//g'
: 45002

Aia · 12-01-2015, 09:40 PM

Code:

echo '"@id": "45002"' | sed 's/"\|@\|id//g'

Code:

: 45002