Question on shell scripts

mp_qqq · 08-16-2010, 03:48 PM

We have Redhat linux 5.5
I am writing a very simple bash shell script which consists of the following:
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MainTest.sh Shell script contents
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DT_STAMP=`date +%Y%m%d%H%M`
echo $DT_STAMP
. ./pos_profile.sh
echo $LOG_FLD
LOG="$LOG_FLD$DT_STAMP.log"
echo "beforelog"
echo $LOG
echo "This is a test" > $LOG

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pos_profile.sh contents
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export RCD_FILE="file_name*.zip"
export LOG_FLD="/home/stage_location/"

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When MainTest.sh is executed, this is the output i get
201008161546
/home/stage_location/
beforelog
201008161546.log

As you can see the LOG variable is set to only DT_STAMP.log. the value of $LOG_FLD is missing

Can somebody please help me understand what is it that I may be missing?

bigrigdriver · 08-16-2010, 04:46 PM

Code:

MainTest.sh Shell script contents
------------------------------------------
DT_STAMP=`date +%Y%m%d%H%M`
echo $DT_STAMP
. ./pos_profile.sh
echo $LOG_FLD
LOG="$LOG_FLD$DT_STAMP.log"

LOG_FLD is not defined.

Tinkster · 08-16-2010, 05:06 PM

And how (from where) are you invoking MainTest.sh?

konsolebox · 08-16-2010, 05:25 PM

That's a very wrong behavior. Can you directly echo "$LOG_FLD$DT_STAMP.log"?

Code:

echo "$LOG_FLD$DT_STAMP.log"