perl array nof hash

zahheb · 08-25-2012, 10:01 AM

suppose $x is a reference to an array of hash then does @y is the array equivalent for the array of hash.

@y = @($x); # typecasting it to an array

and does $y[0]{"some key"} is the proper way to access the elements of the array??

please help

zahheb · 08-25-2012, 10:07 AM

i meant does @y is an array of hash??

chrism01 · 08-26-2012, 06:44 PM

@ = array
% = hash
$ = scalar (single value)

These are the 3 (main) var types in Perl.
Hence an array @arr1 has first element $arr1[0] because the element is a scalar.

What you are talking about is $x is a ref-to-array, each element is a ref-to-hash, so @y = array of hash-refs

Try reading this http://perldoc.perl.org/perldsc.html and indeed bookmark the main site; it's full of good stuff

zahheb · 08-26-2012, 11:37 PM

i didnt mean it......i had asked that if $x is a refernce to an array of hash then what does the below mean

@y= @($x);

does it mean that @y is now the actual array of hash whose refernce was held in $x

this is my question

thanks friends

pan64 · 08-27-2012, 02:30 AM

I think the "cast" works as:
@y = @{$x};
this is what you are looking for. See this page about using references: http://perldoc.perl.org/perlref.html

chrism01 · 08-27-2012, 03:12 AM

Like I said in post #3 (& see my link)

$x is a ref-to-an-array, each element of which is a ref-to-a-hash, so @y = array of hash-refs.

IOW,

Code:

@y= @($x);

effectively takes $x and 'casts it' to an actual array @y (each element of which is a ref-to-a-hash)