[SOLVED] pass source file into awk script

vinaytp · 07-14-2010, 10:31 AM

Hi All,

I have following awk script test.sh

Code:

#!/usr/bin/awk -f
BEGIN { FS=":" }
{
"groups "$1"| cut -d ':' -f2 | cut -d ' ' -f2" | getline GROUP
print "RESULT_START __NAME__:"$1":PRIMARY_GRP:"GROUP":RESULT_END"
}

I am executing this script with following command

Code:

awk -f test.sh /etc/passwd

But I want this to get executed without any arguments like

Code:

./test.sh

I gave executable permission to test.sh script and tried to add /etc/passwd entry in the script. Still I could not succeed.

Please advice

acid_kewpie · 07-14-2010, 10:40 AM

why on earth have you called it test.sh when it's not a shell script???

Personally I would make it a proper shell script, and just pipe the passwd file within the script, and not bother with a specific awk script, as it's pretty tiddly.

Code:

#!/bin/sh
awk 'BEGIN { FS=":" } { 
     "groups "$1"| cut -d ':' -f2 | cut -d ' ' -f2" | getline GROUP
     print "RESULT_START __NAME__:"$1":PRIMARY_GRP:"GROUP":RESULT_END"} 
' /etc/passwd

vinaytp · 07-14-2010, 10:52 AM

Many thanks acid_kewpie for your response.

Quote:

#!/bin/sh
awk 'BEGIN { FS=":" } {
"groups "$1"| cut -d ':' -f2 | cut -d ' ' -f2" | getline GROUP
print "RESULT_START __NAME__:"$1":PRIMARY_GRP:"GROUP":RESULT_END"}
' /etc/passwd

I have already tried this..This gives following error

Code:

[Rohit@localhost test]$ ./test
awk: cmd. line:1:      "groups "$1"| cut -d : -f2 | cut -d 
awk: cmd. line:1:                 ^ unterminated string

grail · 07-14-2010, 11:02 AM

Firstly, the following is not required:

Quote:

awk -f test.sh /etc/passwd

You already have the interpreter at the top of the file so you can simply call it with:

Code:

./test.sh /etc/passwd

I agree I would change the extension in this case as it is not a shell script but an awk one ... maybe test.awk

As for the file, if you do not include a file as an argument it will think you want the script applied to standard input, which will obviously not work.

vinaytp · 07-14-2010, 12:51 PM

Quote:

Originally Posted by grail

Firstly, the following is not required:

You already have the interpreter at the top of the file so you can simply call it with:

Code:

./test.sh /etc/passwd

I agree I would change the extension in this case as it is not a shell script but an awk one ... maybe test.awk

As for the file, if you do not include a file as an argument it will think you want the script applied to standard input, which will obviously not work.

I agree with you grail, But I want to include /etc/passwd inside the script.

I would like to execute the script as

Code:

./test

without /etc/passwd as arguments.

whk · 07-14-2010, 02:30 PM

This may sound kind of over doing it but just make another vi test and paste

awk -f test.sh /etc/passwd

Now u can type ./test

BTW, careful with test cause it's a Bash default. As long as u keep it in path ./

acid_kewpie · 07-14-2010, 03:36 PM

Quote:

Originally Posted by vinaytp

Many thanks acid_kewpie for your response.

I have already tried this..This gives following error

Code:

[Rohit@localhost test]$ ./test
awk: cmd. line:1:      "groups "$1"| cut -d : -f2 | cut -d 
awk: cmd. line:1:                 ^ unterminated string

You should fix your code then, nothing to do with my suggestion, maybe my cutting and pasting though...

igc35 · 07-14-2010, 05:50 PM

I think you may be victim of an old trap that I fell into many years ago.

You cannot call a script "test" if you want to execute it by name. test.sh or test.awk is ok, but test is a built in shell command, which will always take precedence over execution of a script.

Tinkster · 07-14-2010, 06:00 PM

Quote:

Originally Posted by igc35

I think you may be victim of an old trap that I fell into many years ago.

You cannot call a script "test" if you want to execute it by name. test.sh or test.awk is ok, but test is a built in shell command, which will always take precedence over execution of a script.

Ummm ... no.

Code:

./test

is clearly distinct from the bash builtin.

Cheers,
Tink

grail · 07-14-2010, 09:14 PM

Quote:

Originally Posted by vinaytp

I would like to execute the script as
Code:
./test
without /etc/passwd as arguments.

I think you need to re-read my post ... I wasn't saying I couldn't do it, but rather that as far as I know what you want is not possible, from the single script (obviously whk's suggestion will work)

Try reading this page. It is part of the link I gave you previously

Tinkster · 07-14-2010, 10:23 PM

Simplified (less elegant, but working) version:

Code:

awk -F: '{print $1}' /etc/passwd|xargs groups |awk '{print "User: "$1"\t\t primary group: " $3}'

vinaytp · 07-15-2010, 03:38 AM

Quote:

Originally Posted by Tinkster

Simplified (less elegant, but working) version:

Code:

awk -F: '{print $1}' /etc/passwd|xargs groups |awk '{print "User: "$1"\t\t primary group: " $3}'

Yes, This works well..

Thanks everybody for responses.