Need to grep count two phrases in a log file

sd1983benson · 07-08-2015, 10:28 AM

I need to do a grep count for two strings in the same line. Only need the count for what I am looking at.

Tried: grep -c "Phrase part one" | "phrase part two" *.log

I can do grep -c "Phrase part one" *.log just fine. But need to limit it down to where it has a specific phrase part two because phrase part one could be tied to multiple "types" of phrase part two.

I do not get an error. It just hangs there and I have to break out.

Thanks.

HMW · 07-08-2015, 11:31 AM

Quote:

Originally Posted by sd1983benson

I need to do a grep count for two strings in the same line. Only need the count for what I am looking at.

Tried: grep -c "Phrase part one" | "phrase part two" *.log

I can do grep -c "Phrase part one" *.log just fine. But need to limit it down to where it has a specific phrase part two because phrase part one could be tied to multiple "types" of phrase part two.

I do not get an error. It just hangs there and I have to break out.

Thanks.

I am not sure why you need to count. Here's how I would do it:

Code:

egrep 'Phrase part one.*phrase part two|phrase part two.*Phrase part one' phrases.txt 
Phrase part one blah foo bar phrase part two
echo $?
0

As you can see, if grep (or in this case egrep) catches BOTH the phrases on the same line, no matter what phrase appears first, it returns a 0 (success). If you want to, you can expand your script based on the exit code (0) if you need.

Best regards,
HMW

Edit:
The phrases.txt file I tried this on looks like this:

Code:

Phrase part one blah foo bar phrase part two
Phrase part one phrase foobar zap bom bang
phrase part two silmarillion part Phrase part three

Aia · 07-08-2015, 11:48 AM

If we want to stick with grep.

Code:

grep "Phrase part one" *.log | grep -c "phrase part two"