Quote:
Originally Posted by Mr. Alex
Code:
ls -lha /some/dir *5678*
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Since globbing patterns are expanded by the shell before the command is executed,
ls doesn't do any of the locating work here. The only reason to use it at all is if you want the long-form output. For a simple list,
echo is all that's needed.
Use
printf to output the files one per line, or with other fancy formatting.
The '
-a' option has no meaning here either, since dotfiles aren't expanded by the globbing pattern by default. To get hidden files in your output, enable the
dotglob option.
http://mywiki.wooledge.org/glob
Quote:
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Originally Posted by kaldrouby
Code:
i would use this :
ls * | grep 5678*
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Since
ls defaults to all files in the current directory anyway, the "
*" is unneeded. And in order to be read properly by
grep, you'd need to use the "
-1" ("one", not "el") option to print one file per line (and even that would fail if the filenames themselves had newlines in them).
You also have the
grep pattern wrong, since it uses regular expressions, not globbing (which, incidentally you would have to quote first to protect from shell expansion anyway). You only need to use "
grep 5678".
But why bother with all this anyway, when globbing is easier, safer, and lighter (no external commands needed, and unusual characters can't mess it up)?
