Linux project stuck on half the code

Pothole1127 · 04-12-2018, 04:42 PM

Code:

1 #! /bin/bash
  2 echo "**************************************************************"
  3 echo
  4 echo "Katie Carter"
  5 echo "Project 2  CIS 129 Section #01"
  6 date
  7 echo "**************************************************************"
  8 echo
  9 echo "NAME              ON-CALL       PHONE     START TIME"
 10 echo "****              *******       *****     **********"
 11 for day in Monday Tuesday Wednesday Thursday Friday Saturday Sunday
 12 do
 13         name=`grep $day project2.2.input | cut -d " " -f1`
 14                 if [ ! $name ] ; then
 15                      printf Nobody
 16                 fi
 17         time=`grep $day project2.2.input | cut -d " " -f3`
 18                 if [ $time -gt 12 ] ; then
 19                        calctime=`expr $time - 12`
 20                        AMPM=PM
 21                else
 22                        calctime=$time
 23                        AMPM=AM
 24                 fi
 25         phone=`grep $name project2.1.input | cut -d " " -f2`
 26         printf "%-15s %-15s %-15s %-15s\n" $name $day $phone $time
 27 done < project2.1.input < project2.2.input

keefaz · 04-12-2018, 05:30 PM

You don't need the stdin redirection " < project2.1.input < project2.2.input " after done in end of loop because data file is read passing filename as grep argument...

Another way to get time in 12h format if using GNU date

Code:

time=$(grep $day project2.2.input | cut -d " " -f3)
time=$(LC_TIME=C date -d $time +"%I:%M %p")

Pothole1127 · 04-12-2018, 05:32 PM

how would you do the 24 hour format though?

Pothole1127 · 04-12-2018, 05:34 PM

Quote:

Originally Posted by keefaz

You don't need the stdin redirection " < project2.1.input < project2.2.input " after done in end of loop because data file is read passing filename as grep argument...

Another way to get time in 12h format if using GNU date

Code:

time=$(grep $day project2.2.input | cut -d " " -f3)
time=$(LC_TIME=C date -d $time +"%I:%M %p")

How do you do the 24 hour format?

keefaz · 04-12-2018, 05:37 PM

For 24h format

Code:

time=$(grep $day project2.2.input | cut -d " " -f3)
time=$(date -d $time +"%H:%M")

Have a look at date manual (man date)