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I have one sort of file with the same name in many sub-directories in the same mother folder, I need to pull out the last line in each file of those files I don't know how to do that in once, it takes very long time to go to each sub directory and in to the file and (tail -1) for each one to take the last line, I tried with grep command but I failed, any idea please?
Perhaps the easiest way to print the last line of a file is to use
Code:
sed -n '$p' input.file
To find all the files, use the "find" command - it has an "-exec" option that will enable you to run the sed on each file found.
That should do it all for you - the hard part is learning the "find" parameters. See how you go.
Hi syg00,I am new using linux and never used find but after u told me I read about it and found the solution for my problm with this beautiful line ( find . -iname 'fe.dat' -exec tail -n1 {} \, can you tell me what this bracket does or this part {} \; of the line?
Yes this script is to find the files and it helped my first problem, but now my other concern is to run another script on many directory, I have many directories in one main directory what I do is open each directory and run a specific script that I have to get the output files, it takes a long time to open each directory and run the script in it.
My question was is it possible to find the directories and run the script on them at the same time.
Commands xargs and parallel will keep a number of processes running. So if you find the paths of the directories, either one of those can then create a queue of processes filled until it runs out of work to do. The man page for xargs should get you going, and parallel may be in your repository (it's in Gnu/Debian jessie, for example).
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