[SOLVED] grep -c not working in Linux

nishanthp82 · 01-26-2012, 02:40 PM

#!/bin/ksh
STATUS1=grep -c "error_phrases" /home/psbatch/batch/error.log
echo "STATUS1 (error phrases grep, 0=good): $STATUS1"

i try to get the count of "error_phrase" word in error.log but the shell says

./test1.ksh[2]: -c: not found [No such file or directory]

please help!

jhwilliams · 01-26-2012, 02:41 PM

Code:

STATUS1=$(grep -c "error_phrases" /home/psbatch/batch/error.log)
echo "STATUS1 (error phrases grep, 0=good): $STATUS1"

nishanthp82 · 01-26-2012, 03:17 PM

STATUS1=$(grep -cf $SCRDIR error_phrases)

there is a file called error_phrases but Linux is not picking up

any help?

bsat · 01-27-2012, 12:32 AM

Which directory does the file exist in ? If it is not in your present working directory then provide the full path.

devUnix · 01-27-2012, 01:01 AM

Nishant:

This is not a valid stament/command:

Code:

STATUS1=grep -c "error_phrases" /home/psbatch/batch/error.log

You must change it to:

Code:

STATUS1=`grep -c "error_phrases" /home/psbatch/batch/error.log`

Notice that those are backticks and not apostrophies or single quotes.

or change it to:

Code:

STATUS1=$(grep -cf $SCRDIR error_phrases)

just waht you have posted above and it seems okay.

Now let me point out something here:

What is "$SCRDIR" doing in there? Is it the directory in which you have a log file to search for the patter in?

Note: "-f" option means you are specifying a file that contains the "pattern/keywords" you are searching for.

You would rather use:

Code:

 grep -c error_word_of_your_interest /full/path/to/your/log/file.log

First run the above command and check its result. If it is okay then move on to this step:

Code:

 COUNT=`grep -c error_word_of_your_interest /full/path/to/your/log/file.log`

or

Code:

 
COUNT=$(grep -c error_word_of_your_interest /full/path/to/your/log/file.log) 
echo "Number of Errors Found: " $COUNT

Please let us know if the above solution does not work for you. Post your exact script hre.