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Old 01-26-2012, 03:40 PM   #1
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grep -c not working in Linux

STATUS1=grep -c "error_phrases" /home/psbatch/batch/error.log
echo "STATUS1 (error phrases grep, 0=good): $STATUS1"

i try to get the count of "error_phrase" word in error.log but the shell says

./test1.ksh[2]: -c: not found [No such file or directory]

please help!
Old 01-26-2012, 03:41 PM   #2
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STATUS1=$(grep -c "error_phrases" /home/psbatch/batch/error.log)
echo "STATUS1 (error phrases grep, 0=good): $STATUS1"
Old 01-26-2012, 04:17 PM   #3
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STATUS1=$(grep -cf $SCRDIR error_phrases)

there is a file called error_phrases but Linux is not picking up

any help?
Old 01-27-2012, 01:32 AM   #4
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Which directory does the file exist in ? If it is not in your present working directory then provide the full path.
Old 01-27-2012, 02:01 AM   #5
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Distribution: RHEL 5.1 on My PC, & SunOS / Sun Solaris, RHEL, SuSe, Debian, FreeBSD and other Linux flavors @ Work
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This is not a valid stament/command:

STATUS1=grep -c "error_phrases" /home/psbatch/batch/error.log
You must change it to:

STATUS1=`grep -c "error_phrases" /home/psbatch/batch/error.log`
Notice that those are backticks and not apostrophies or single quotes.

or change it to:

STATUS1=$(grep -cf $SCRDIR error_phrases)
just waht you have posted above and it seems okay.

Now let me point out something here:

What is "$SCRDIR" doing in there? Is it the directory in which you have a log file to search for the patter in?

Note: "-f" option means you are specifying a file that contains the "pattern/keywords" you are searching for.

You would rather use:

 grep -c error_word_of_your_interest /full/path/to/your/log/file.log
First run the above command and check its result. If it is okay then move on to this step:

 COUNT=`grep -c error_word_of_your_interest /full/path/to/your/log/file.log`

COUNT=$(grep -c error_word_of_your_interest /full/path/to/your/log/file.log) 
echo "Number of Errors Found: " $COUNT

Please let us know if the above solution does not work for you. Post your exact script hre.
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