[SOLVED] date; how to display as i.e Oct 1 *note the extra space*

greenpool · 10-01-2011, 12:19 AM

Hi,

i'm writing a script that greps the logs based on month/date.

when i found this:

Code:

Oct  1 14:41:01 ubuntu CRON[2446]: pam_unix(cron:session): session closed for user smmsp
Oct  1 14:44:55 ubuntu gnome-screensaver-dialog: gkr-pam: unlocked login keyring
Oct  1 14:58:06 ubuntu gnome-screensaver-dialog: gkr-pam: unlocked login keyring

as you can see it doesn't record the date as "Oct 01" and instead of "Oct 1" it has a a space for the 0 thus becoming "Oct 1" (double spaced)

but when the date changes to something with 2 digits like "Aug 14" its normal:

Code:

Aug 14 12:17:01 ubuntu CRON[2052]: pam_unix(cron:session): session opened for user root by (uid=0)
Aug 14 12:17:01 ubuntu CRON[2052]: pam_unix(cron:session): session closed for user root

so my static code to grep the date doesn't work. i'm using ubuntu and the logs were from /var/logs/auth.log

my code was:

Code:

SEARCHDATE=$(date +%b\ %d)

any comments on how to get this working? thnaks.

macemoneta · 10-01-2011, 12:41 AM

From 'man date':

Quote:

%e day of month, space padded; same as %_d