Hi!

I have question about output order in my manually created log file.

crontab -l:
0 * * * * /my/script/run.sh >/my/log/crontab.log 2>&1

Now, I have noticed that order in /my/log/crontab.log file is not same as command order.

i.e.

my run.sh script:

command1
command2
command3

in my crontab.log is

output_of_command1
output_of_command3
output_of_command2

Is this "normal"?

THX

edit:

command2 is ftp "here_document".

i.e.

my ftp script:

#!/bin/ksh
ftp -i server1 <<END
bin
lcd /dir1
cd dir2
mput *.*
!rm *.*
lcd /dir3
cd dir4
mput *.*
!rm *.*
END

my crontab.log file:

rm: *.* non-existent
rm: *.* non-existent
Local directory now /dir1
Local directory now /dir3

As you can see, first two ouputs are rm: (although in script they are at 2. and 4. place)
THX

The reason for this is that the output isn't written until the command is done. Your "rm" commands aren't being run before or after the ftp command, they are being run during the ftp command. They end first and are therefore written first. If you want the order to be the way you are looking for it, change your script to:

However, I don't really suggest doing this. If all you wanted to do was know why it is outputting things in an unexpected order, the reason is stated above.

HTH

Forrest

But commands are effectively (sorry I don't know "effectively" is the right word) executed in order they are written?

They are run in the order written and the logs are written in the order the commands complete.

HTH

Forrest