Command to list files starting with uppercase letter

djfog · 07-04-2008, 04:48 AM

Hi to all.Well I have come up with this command:

Code:

ls -a|grep '^[A-Z]'

but it is also lists the directories.I'm looking for a command to list only files.
Thanks in advance..

indeliblestamp · 07-04-2008, 05:16 AM

Hint: You can also use ls -a [A-Z]* instead of piping ls to grep.
To list only files, use this:

Code:

ls -lad [A-Z]* | grep -v ^d | awk '{print $9}'

You should see the man pages for ls, grep and awk for details, but in short, what the command does is:
-- listing all files but without expanding directories
-- grep all lines that don't start with 'd' (i.e. only files, symlinks, etc)
-- cut out the files column from the normal ls -l listing

Mr. C. · 07-04-2008, 05:17 AM

See the -F option for ls. Note how it treats files, directories, etc. uniquely.

djfog · 07-04-2008, 05:21 AM

Well,I found that the command :

Code:

ls -ap|grep '^[A-Z].*[^/]$'

does the job.But now I'm having another problem as I want to find the number of files that were created a specific month.I tried something similar to the previous command,but It didn't work.Here is my code:

Code:

read -p "give the month in 2 digit number" month
echo "the number of files created on $month is:"
ls -ap|grep '\-\'$month'\-[^/]$'|wc -l

Any ideas where am I mistaken or how to fix it..?
Thanks in advance...

indeliblestamp · 07-04-2008, 05:24 AM

oops. Agreed, ls -F with a single grep is a much neater solution.

djfog · 07-04-2008, 05:30 AM

Thanks for your advices.This command worked:

Code:

ls -l|grep '\-\'$month'\-'|grep -v ^d|wc -l