Combine multiple one column text file into one text file with multiple colum
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After googling for some time I finally found the simplest solution to my problem
Code:
# paste file1 file2 | sed 's/\t/,/g'
will do the trick.
I've try to use while loop and read command but my knowledge of shell script is not very good. Can you post the solution using while and read command. I'm curios to see how the solution work.
This script work using perl, the previous one contains some mistakes
open FILE1, "/tmp/file1.txt" or die "could not open file1.txt" ;
open FILE2, "/tmp/file2.txt" or die "could not open file2.txt" ;
open FILE3, "/tmp/file3.txt" or die "could not open file3.txt" ;
$file1 = <FILE1>; chomp $file1 ;
$file2 = <FILE2>; chomp $file2 ;
$file3 = <FILE3>; chomp $file3 ;
while ($file1 or $file2 or $file3) {
print "$file1 $file2 $file3 \n";
$file1 = <FILE1>; chomp $file1 ;
$file2 = <FILE2>; chomp $file2 ;
$file3 = <FILE3>; chomp $file3 ;
}
close FILE1 ;
close FILE2 ;
close FILE3 ;
I trapped myself by a too fast answer, but I'm able to give a solution, probably not the best, but this one works and was verified ...
#!/bin/bash
let nbline=0
let nbline2=0
let nbline3=0
while read ligne ; do t1[$nbline]=$ligne ; let nbline=$nbline+1 ; done < /tmp/file1.txt ;
while read ligne ; do t2[$nbline2]=$ligne ; let nbline2=$nbline2+1 ; done < /tmp/file2.txt ;
while read ligne ; do t3[$nbline3]=$ligne ; let nbline3=$nbline3+1 ; done < /tmp/file3.txt ;
if [ $nbline2 > $nbline ] ; then let nbline=$nbline2; fi
if [ $nbline3 > $nbline ] ; then let nbline=$nbline3; fi
for ((l=0;$l<$nbline;l=$l+1)) ; do echo ${t1[$l]} ${t2[$l]} ${t3[$l]} ; done
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