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I got a simple question, but Google has not assisted me in this query.
I am using "if" to force a word under the condition that the first letter of that word must be a letter of the alphabet, regardless of capitalization, using the " "" != "" " syntax.
Like so:
Code:
if [[ "$interface" != "WHAT DO I PUT HERE?" ]] ; then
echo "Invalid input"
exit 1
fi
Thank you in advance.
Last edited by lupusarcanus; 03-14-2010 at 01:01 PM.
Reason: better code
#!/bin/bash
test="gtw3 tw"
if [[ "$test" =~ ^[A-Za-z] ]]; then
echo "ok"
else
echo "Invalid input"
exit 1
fi
That did work. However, for sake of code cleanliness, I was hoping for the syntax to say: If the variable does not begin with a letter of the alphabet (regardless of capitalization), then display an error message and exit with status code 1. Is this possible?
The reason is because if I go with your code, this is how it would look:
Code:
if [[ "$interface" =~ ^[A-Za-z] ]]; then
echo "" >/dev/null
else
echo "
ERROR 7: No usable interface label detected.
"
exit 1
fi
Thank you for your reply. You gave much more information than my weak Googling skills gave me.
Last edited by lupusarcanus; 03-14-2010 at 12:54 PM.
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