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Really? I can think of several ways to do that, but I wouldn't call any of them "trivial." Simplest I've come up with:
Code:
for i in ${!name[@]}; do [[ $i =~ ^1 ]] && echo $i; done | wc -l
Or, doing a bit more in the shell to avoid the wc invocation:
Code:
n=0; for i in ${!name[@]}; do [[ $i =~ ^1 ]] && ((++n)); done; echo $n
Thanks rknichols for your helpful solution and gratitude atleast you do not think it was trivial.
It solved my issue. Used your code in my loop and adjust little according to my script and it worked like a charm.
Thanks again.
Thanks rknichols for your helpful solution and gratitude atleast you do not think it was trivial.
I rather liked @grail's solution, which in one shot gives you an array with the counts for each of the leading digits as long as there are no indices longer than 2 digits, but I wouldn't classify that one as "trivial" either. "Clever", yes.
Sorry if I upset anyone with my comment. As it popped into my head immediately it did seem trivial to me (sometime forget this is noob section and so learning means not trivial )
Good point on the indices not longer than 2 digits. I did have an alternative, but wasn't sure if it went higher if we then wanted 11 out of 110 or just 1
Assuming only first digit, slight change is:
Code:
for i in ${!name[*]};do (( count[${i:0:1}]++ ));done
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