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Old 07-24-2006, 11:21 AM   #1
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Question bad: help me urgent just simple assert.h prob

int main (void)
int a, b, cnt=0, i;
for(i=0; i <1000; ++i){
a= rand() % 3 + 1;
b= rand() % 30 + 1;
if (b - a <= 1)
assert (b - a > 2);
printf("count=%d\n", ++cnt);
return 0;

that's the program and i cant understand how it works. i tried running the program and get different count results with two different computer i used. i tried researching about the functions time.h ; rand() and assert.h using the book A Book on C where this exercise can be found but no vivid explanation on how this works. i tried changing the values of %30 to % 20 and %10. i get different count results but i found no logic on it.please help me answer these questions too, 1.what values of a and b cause the assertion to fail? i think its 2 and 4, 3 and 5, 3 and 4. is this right? 2. how many times do u expect to go through the loop? number of times the program is executed? and the number of iterations produced per execution of the program? i dont know how this programs really works so i don't know how to track the number of times
guys please help me thanks...

Last edited by icylicious; 07-24-2006 at 11:38 AM.
Old 07-24-2006, 11:25 AM   #2
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Originally Posted by LQ RUles
Do not expect LQ members to do your homework - you will learn much more by doing it yourself.
See above.

You have provided no information on what you have done to try and solve the problem yourself before you want people to do it for you
Old 07-24-2006, 01:17 PM   #3
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Please do not post the same thread in more than one forum. Picking the most relevant forum and posting it once there makes it easier for other members to help you and keeps the discussion all in one place.
Old 07-24-2006, 01:25 PM   #4
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Per unspawns comment I'm closing this one. Programming to me seems the
most reasonable spot, please take FUPS there.

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