Array problem in Bash

basildon · 09-09-2008, 05:34 AM

Hi

Could anyone explain what I'm doing wrong in the example below. I'm trying to read characters into an array one at a time, but with no success.

Thanks

#!/bin/bash

echo "Enter the filename xx "
read answer
z=$(ls -l $answer);
int=0;

while [ $int -lt 10 ]
do
val=${z:$int:1} ### reads value 1 character at a time
FOO[$int]=$val ### puts value in array
int=$(($int + 1))
echo $val ### This echos value to screen
echo ${FOO[${int}]} ### This doesn't just gives blanks
done

colucix · 09-09-2008, 05:45 AM

Basically you increment the int variable before echoing the value: you assign the first value then echo the second which is still null, you assign the second and echo the third and so on.

basildon · 09-09-2008, 05:56 AM

Many thanks