Linux - NewbieThis Linux forum is for members that are new to Linux.
Just starting out and have a question?
If it is not in the man pages or the how-to's this is the place!
Notices
Welcome to LinuxQuestions.org, a friendly and active Linux Community.
You are currently viewing LQ as a guest. By joining our community you will have the ability to post topics, receive our newsletter, use the advanced search, subscribe to threads and access many other special features. Registration is quick, simple and absolutely free. Join our community today!
Note that registered members see fewer ads, and ContentLink is completely disabled once you log in.
If you have any problems with the registration process or your account login, please contact us. If you need to reset your password, click here.
Having a problem logging in? Please visit this page to clear all LQ-related cookies.
Get a virtual cloud desktop with the Linux distro that you want in less than five minutes with Shells! With over 10 pre-installed distros to choose from, the worry-free installation life is here! Whether you are a digital nomad or just looking for flexibility, Shells can put your Linux machine on the device that you want to use.
Exclusive for LQ members, get up to 45% off per month. Click here for more info.
#vi script1
ftp ip <<EOF
lcd dir1
cd dir2
put ${1}
! script2
bye
EOF
then I run it as
#script1 myfile
then it could ftp myfile to remote site , it works fine , that mean ${1} is the parameter
In the script1 , it will run another script ( script2) , now I would like this scripts also use the parameter , for example , I would like to display the parameter of ${1} like below , what can i do ?
I tried to edit script2 as below
#vi script2
echo ${1}
what I expect the result is myfile , but it didn't , can advise what can i do ? thx
I am not sure I understand you correctly, but nonetheless, if you call script2 from within script1, you need to pass it the argument, just like you pass it to script1.
I am not sure I understand you correctly, but nonetheless, if you call script2 from within script1, you need to pass it the argument, just like you pass it to script1.
LinuxQuestions.org is looking for people interested in writing
Editorials, Articles, Reviews, and more. If you'd like to contribute
content, let us know.