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Old 03-11-2003, 10:49 AM   #1
WeNdeL
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Question network address ranges


I am having trrouble wrapping my head around this certain form of cidr notation...

with this info:

Network = 192.168.1.128 (last byte = 1000 0000)
Netmask = 255.255.255.192 (last byte = 1100 0000)
First address: 192.168.1.128 (including network)
Last address: 192.168.1.191 (including broadcast)

How can the address range be represented by:

192.168.1.128/26

I can't seem to make since of this in my head... I fully understand the concepts behind this network and all it entails but don't seem to follow this form of notation. What is it telling me?
 
Old 03-11-2003, 11:08 AM   #2
WeNdeL
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ok...

looks to me like this notation is telling me that the hosts within this network range from:

192 168 1 128
1100 0000 1010 1000 0000 0001 1000 0000

to

192 168 1 191
1100 0000 1010 1000 0000 0001 1011 1111

all three together:

1100 0000 1010 1000 0000 0001 1000 0000
1100 0000 1010 1000 0000 0001 1011 1111
1111 1111 1111 1111 1111 1111 1100 0000

yields the address range resulting in a bitmask of 26 bits...



Weeeeeeeeeeeeeeeeeee!!!!

edit: which one could gather from the netmask...

Last edited by WeNdeL; 03-11-2003 at 11:11 AM.
 
Old 03-11-2003, 11:33 AM   #3
baldy3105
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Correct. The network is derived by from the IP address by ANDing it with the subnet mask -

192.168.1.128
AND
255.255.255.192 (/26)

or

11000000 10101000 00000001 10000000
AND
11111111 11111111 11111111 11000000
=
11000000 10101000 00000001 10000000 or 192.168.1.128



Do the same with 192.168.1.191 -

11000000 10101000 00000001 10111111
AND
11111111 11111111 11111111 11000000
=
11000000 10101000 00000001 10000000 or 192.168.1.128

See, same network! Try the same thing with 192.168.1.192 and you'll see that the resultant network is different.
 
Old 03-11-2003, 11:41 AM   #4
acid_kewpie
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wow, that makes sense.... i've always been ropey with that... so i just always pretended it didn't exist!
 
Old 03-12-2003, 10:56 AM   #5
baldy3105
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Hey, a million ostrich's can't be wrong!
 
  


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