small bash script issue

zoomzoom · 06-07-2004, 02:47 PM

Hallo,

maybe this fits better in the newbie forum:

Code:

for ((i=$#;i>0;i--)); do ...; done

in the do-part, i know want to output the $1,$2,$3,... depending on the current value of i.

I tried various things like 'echo $($i0)' or 'echo $$i0' or 'echo ${$i0}' ...

So, how do you do this?

thx
bye

homey · 06-07-2004, 03:22 PM

Try this one...

echo -n "$i"

zoomzoom · 06-07-2004, 03:31 PM

doesn't work. this outputs the variable i.
What i want to output is the VARIABLE/PARAMETER $1,$2,...

example:

echo $1, if i=1,
echo $2, if i=2,
echo $3, if i=3, and so on...

i hope i explained it better now ...

jschiwal · 06-08-2004, 09:46 AM

If you want to loop through the arguments themselves
you could assign i to these values to begin with:

#!/bin/bash
for i in "$*"; do
echo $i
done

marghorp · 06-08-2004, 12:41 PM

for i in 1 2 3 4 5 6 7
do
echo $i
done

jschiwal · 06-08-2004, 12:55 PM

Sorry, marghorp, but your scripts prints out the numbers of I rather than the corresponding arguments to the script.

marghorp · 06-08-2004, 01:07 PM

Sorry for that, I completely missed the point here. Kind a noob myself when it comes to bash scripting, yet.

BrianK · 06-08-2004, 06:33 PM

maybe approaching it from a different angle will help. I assume you have a bunch of variables assigned, like $1="foo" $2="bar" $3="gah", etc.

Could you put those values into an array and then loop thruogh the array? You could do something like this in that case (granted, this is tcsh, but bash is similar):

Code:

set array=(foo bar gah)
foreach i ($array)
  echo $i
end