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> /tmp/size
for i in `ls -lrth /home | grep ^d | awk '{print $9}' | grep -v lost+found`;do du -sh $i >> /tmp/size; done;
you are going a round about way to finding directories in the /home path. Also, if directory names have spaces, your awk command with $9 won't work. an easier way is to use find, just an example
you are going a round about way to finding directories in the /home path. Also, if directory names have spaces, your awk command with $9 won't work. an easier way is to use find, just an example
Code:
$ find /home -type d -print0 | xargs -0 du -sh
Thanks, ghostdog. But I checked it on my system, this commands includes sub-directories too. This command is also printing space of all subdirectories
However, the OP just wants the size of the home directories of users.
Thanks, ghostdog. But I checked it on my system, this commands includes sub-directories too. This command is also printing space of all subdirectories
However, the OP just wants the size of the home directories of users.
depth of recursive can be fixed with -prune or -maxdepth (GNU find). you have misunderstood what i mean by directory names with spaces
Code:
# ls -1
dir with space
t1
t2
test.txt
test with space.xml
test.xml
# find . -type d -print0 | xargs -0 du -sh
40K .
8.0K ./t1
8.0K ./t2
8.0K ./dir with space
the command correctly shows directory with spaces and its size.
whereas your for loop:
Code:
$ for i in `ls -lrth | grep ^d | awk '{print $9}'`; do echo "$i"; done
with
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