getting image size (imagemagick)

btb · 08-12-2005, 04:25 PM

hi all. I would like to get the dimensions (actually just width is good enough) for an image from the shell prompt.

"identify image.jpg" from imagemagick gives the critical information, but I want to write a batch script which is conditioned only on width. how can I find that out?

identify -size does'nt work for me either. :(

thanks for your help.

btb · 08-12-2005, 05:09 PM

Im sorry, I guess this should've gone in the newbie forum. I just can't figure out how to delete this post.

jonthelam · 08-12-2005, 05:55 PM

Try this:

Code:

identify -format "%f,%w,%h"

%f = filesize
%w = width
%h = height

There's more options if you need it. Find it here.

I think the ImageMagick forums might be a better place to post questions.

btb · 08-12-2005, 06:00 PM

thank you!

m_pahlevanzadeh · 10-15-2013, 01:32 PM

You can use :

Code:

php -r "print_r(getimagesize('file:///archives/Picture/12 farvardin/20120331_013.jpg'));"

in command line,

Also you can replace

Code:

file://

with

Code:

http://

John VV · 10-15-2013, 01:44 PM

m_pahlevanzadeh
you are aware that this thread is from 2005 .
right?

m_pahlevanzadeh · 10-15-2013, 02:39 PM

Yes, i answered because when a person has this problem can solve from my solution.