Find command

SmurfGGM · 06-13-2014, 06:31 AM

Hi readers.

I am trying to run a find command and would like to display a message on any of the files that are not found.

I have files in my file_list.tmp that don't exist and would like that to be highlighted in the code below ..

Code:

while read line
do
find $CFXHOME -type f -name $line | grep -v fixes >> $FIXDIR/efin_files.tmp
done < file_list.tmp
backupcount=`wc -l efin_files.tmp | cut -f1 -d' '`

Many thanks.

smallpond · 06-13-2014, 06:46 AM

Maybe something like

Code:

while read line
do
  FILES=$(find $CFXHOME -type f -name $line)
  if [ -z '$FILES" ] ;then
      echo "Missing: $line"
  else
      echo $FILES | grep -v fixes >> $FIXDIR/efin_files.tmp
  fi
done < file_list.tmp
backupcount=`wc -l efin_files.tmp | cut -f1 -d' '`

SmurfGGM · 06-13-2014, 07:11 AM

Thanks but that didn't work.

Only 1 file (instead of 9) is being written to $FIXDIR/efin_files.tmp and FILES=$(find $CFXHOME -type f -name $line) isn't producing anything

rknichols · 06-13-2014, 08:22 AM

Change that find command to

Code:

find "$CFXHOME/$line" -type f ! -name '*fixes*' >> "$FIXDIR"/efin_files.tmp

Now, find will complain if the file doesn't exist, and filtering out names that contain "fixes" is done right there by find, eliminating the need for grep. I've also added quoting to protect against names containing spaces or characters special to the shell. That might not be a problem in this case, but it's just good practice.

The only thing that this will silently ignore would be a name that exists but fails the "-type f" test.