cant "source" bash script with arguments (PATH updating)

monkey_king · 12-29-2008, 04:06 AM

I'm trying to install icc compiler 11.0

I've got this script here located at /opt/intel/compiler/11.0/0.74/bin/iccvars.sh

Code:

#!/bin/bash
case "$1" in
  ia32)
      if [ -e /intel/cc/10.0.023/intel/Compiler/11.0/074/bin/ia32/iccvars_ia32.sh ]; then
         . /intel/cc/10.0.023/intel/Compiler/11.0/074/bin/ia32/iccvars_ia32.sh 
      fi
      ;;
  intel64)
      if [ -e /intel/cc/10.0.023/intel/Compiler/11.0/074/bin/intel64/iccvars_intel64.sh ]; then
         . /intel/cc/10.0.023/intel/Compiler/11.0/074/bin/intel64/iccvars_intel64.sh 
      fi
      ;;
esac

The files iccvars_ia32.sh and 64.sh, should update the PATH.

If I run
source iccvars_ia32.sh it works.
But if i try to call this wrapper called iccvars.sh it doesn't update anything.

Thanks in advance

i92guboj · 12-29-2008, 04:43 AM

In any case you would need to source the wrapper. Otherwise the scripts would be sourced withing the subshell where the iccvars.sh wrapper is run, which won't modify the parent environment (I guess that's what you intend).

monkey_king · 12-29-2008, 08:10 AM

hi,
maybe I wasn't clear.

Even if I try sourcing the wrapper it doesn't work

colucix · 12-29-2008, 08:39 AM

A similar construct works for me. Are you sure about the passed argument? What command line did you used to source the wrapper and where did you put it (e.g. in $HOME/.bashrc)?

monkey_king · 12-30-2008, 04:08 AM

No I don't put the source command in any dotfiles,
I just source it in the promt.

I type in

source iccvars.sh

colucix · 12-30-2008, 04:34 AM

Quote:

Originally Posted by monkey_king

I type in

source iccvars.sh

I take it literally: if you don't pass any argument, no condition is satisfied in the case construct. You have to do one of the following:

Code:

source iccvars.sh ia32
source iccvars.sh intel64