[SOLVED] C programming linux

unkie888 · 12-23-2008, 11:09 AM

According to the man page, strtol should set the errno:

Quote:

Since strtol() can legitimately return 0, LONG_MAX, or LONG_MIN (LLONG_MAX or LLONG_MIN for strtoll()) on both success and failure,
the calling program should set errno to 0 before the call, and then determine if an error occurred by checking whether errno has a
non-zero value after the call.

However, it appears not to:

Code:

#include <stdio.h>
#include <errno.h>
#include <string.h>
#include <stdlib.h>

main(argc, argv)
char **argv;
{
    char *val = "turdburger";
    int ival;

    errno = 0;

    ival = strtol(val,(char **)NULL, 10);

    if ( errno )
    {
      printf("FAIL - (%d)(%s)\n",errno,strerror(errno));
    }
    else
    {
      printf("apparently it worked %s=%d \n",val,ival);
    }
}


[root]# ./a.out
apparently it worked turdburger=0

[root]# uname -a
Linux xxx 2.6.22.14-72.fc6 #1 SMP Wed Nov 21 14:10:25 EST 2007 x86_64 x86_64 x86_64 GNU/Linux

Guttorm · 12-23-2008, 12:33 PM

Hi

But before that:

Quote:

The strtol() function converts the initial part of the string in nptr
to a long integer value according to the given base, which must be
between 2 and 36 inclusive, or be the special value 0.

This means it only uses the digit chacacters at the left of the string. It stops at the first non-digit, and returns the number. It's zero for no digits at all. The only error it returns, is if the number is too big or too low for "long" variables.

unkie888 · 12-24-2008, 06:06 AM

Quote:

Originally Posted by Guttorm

Hi

But before that:

This means it only uses the digit chacacters at the left of the string. It stops at the first non-digit, and returns the number. It's zero for no digits at all. The only error it returns, is if the number is too big or too low for "long" variables.

Is there anyway in C to check weather a string is indeed an integer value?

Guttorm · 12-24-2008, 07:18 AM

You mean to check if the string contains digits only? I don't think there is one, but it's easy to make one - looping thru the characters and check each with isdigit.

Another way:

Code:

if (strspn(s,"0123456789") == strlen(s)) {
  /* s contains only digits */
}

unkie888 · 12-26-2008, 09:29 AM

Quote:

Originally Posted by Guttorm

Code:

if (strspn(s,"0123456789") == strlen(s)) {
  /* s contains only digits */
}

I really liked that strspn tip.