BASH script question

FireRaven · 03-08-2012, 05:37 PM

Hi guys, a quick simple 3 line bash script - the echo's say it all.
Why does the last line echo when the second last echo doesn't?

I would expect my script to exit at line 2 and not print line 3, yet it prints line 3?

Code:

#!/bin/bash
[[ 1 == 1 ]] && (echo 'Should see me!';exit 0;echo 'But you cant see me?')
echo 'Should NOT see me!'

Output:

Code:

user@ubuntu:/tmp$ ./test.sh 
Should see me!
Should NOT see me!

kbp · 03-08-2012, 06:18 PM

Commands placed inside '()' are run in a subshell, you're only exiting the subshell, not the parent. Try '{}' to execute in the current shell, don't forget a trailing ';'

Code:

#!/bin/bash
[[ 1 == 1 ]] && { echo 'Should see me!';exit 0;echo 'But you cant see me?'; }
echo 'Should NOT see me!'

FireRaven · 03-08-2012, 06:38 PM

Thanks kbp that works.
I didn't know that ran in a subshell, thought they were written with $().