[SOLVED] Bash: repeating command

fajarpri · 07-16-2013, 09:37 PM

Hi all,
I have this bash script. How do I make it to repeat like 50 times with 1 second delay in between? Thanks in advance

Code:

#!/bin/bash
pdbedit -z -u $1
pdbedit -c "[]" $1
pdbedit -Lv $1

Ser Olmy · 07-16-2013, 09:44 PM

for loops can be used to repeat a command or a set of commands any number of times. The sleep command is used to introduce a delay.

evo2 · 07-16-2013, 09:45 PM

Hi,

Quote:

Originally Posted by fajarpri

Hi all,
I have this bash script. How do I make it to repeat like 50 times with 1 second delay in between? Thanks in advance

Code:

#!/bin/bash
pdbedit -z -u $1
pdbedit -c "[]" $1
pdbedit -Lv $1

You should look up how to use loops in bash scripts, and also investigate the sleep command. Entering "bash for loop" into your favourite search engine, and "man sleep" into your terminal should provide the information you need.

HTH,

Evo2.

fajarpri · 07-16-2013, 10:03 PM

Thank you!
Got help from Goldfish at bash IRC.

#!/bin/bash
for i in {1..50}
do
pdbedit -z -u "$1"
pdbedit -c "[]" "$1"
pdbedit -Lv "$1"
sleep 1
done