Hi,
I have the following script:

#!/bin/sh
/bin/mv /root/dump1090/radar.txt /root/logs/radar.txt
/bin/touch /root/logs/dump1090/radar.txt
/usr/bin/awk '!_[$1]++' /root/logs/radar.txt >/root/logs/radar1.txt
/bin/sed 's/$/,20140001,//' /root/logs/radar0.txt >/root/logs/radar1.txt
/bin/mv /root/logs/radar2.txt /root/logs/radar.csv
/bin/mv /root/logs/radar.csv /root/logs/"radar-`date +%Y%m%d`.csv"



How do I get the date in the format of

YYYY-MM-DD added to this line after the second comma:

/bin/sed 's/$/,20140001,//' /root/logs/radar0.txt >/root/logs/radar1.txt

thanks in advance
David

Can you paste the section where you need the modification in radar1.txt post running sed on it. Just use bold tag to highlight it.

Rather than us provide the answer, perhaps you should show us what you tried - and what you don't understand about why it didn't work.

Its on this line :

I have tried adding `date +%Y%m%d` to it :

but it didnt run

Use doube quotes(") rather than single (') around the substitution text - that way the date command will get evaluated by the shell.