Linux From ScratchThis Forum is for the discussion of LFS.
LFS is a project that provides you with the steps necessary to build your own custom Linux system.
Notices
Welcome to LinuxQuestions.org, a friendly and active Linux Community.
You are currently viewing LQ as a guest. By joining our community you will have the ability to post topics, receive our newsletter, use the advanced search, subscribe to threads and access many other special features. Registration is quick, simple and absolutely free. Join our community today!
Note that registered members see fewer ads, and ContentLink is completely disabled once you log in.
If you have any problems with the registration process or your account login, please contact us. If you need to reset your password, click here.
Having a problem logging in? Please visit this page to clear all LQ-related cookies.
Get a virtual cloud desktop with the Linux distro that you want in less than five minutes with Shells! With over 10 pre-installed distros to choose from, the worry-free installation life is here! Whether you are a digital nomad or just looking for flexibility, Shells can put your Linux machine on the device that you want to use.
Exclusive for LQ members, get up to 45% off per month. Click here for more info.
It is a way of saying the value of the variable that is named the value of this variable.
Here is an example. Say you set the value of FOO to asdf, and you set the value of BAR to foo. You can get the value of FOO with ${!BAR}. Here it is in code w/ an example of why you would want to do it:
Code:
FOO1='This is fun'
FOO2='So is this'
FOO3='No fun here'
for BAR in FOO1 FOO2 FOO3 ; do
echo ${!BAR}
done
the value of the variable that is named the value of this variable
Arrgh!!!---instant headache....
Obviously not negation in this context...
From ABS**:
Quote:
Example 34−2. Indirect variable references − the new way
#!/bin/bash
# Indirect variable referencing.
# This has a few of the attributes of references in C++.
a=letter_of_alphabet
letter_of_alphabet=z
echo "a = $a" # Direct reference.
echo "Now a = ${!a}" # Indirect reference.
# The ${!variable} notation is greatly superior to the old "eval var1=\$$var2"
echo
t=table_cell_3
table_cell_3=24
echo "t = ${!t}" # t = 24
table_cell_3=387
echo "Value of t changed to ${!t}" # 387
**The Advanced Bash Scripting Guide (AKA the "boat anchor")---get it at http://tldp.org
LinuxQuestions.org is looking for people interested in writing
Editorials, Articles, Reviews, and more. If you'd like to contribute
content, let us know.