grep lines between occurances of a pattern

ksri07091983 · 04-26-2009, 01:14 AM

Hi,

I have a requirement like, I need to grep all the lines that occur between a pattern.

For e.g.,

Code:

$cat testfile 
123654 asdfasf
46546 asfasd
23456 abcd
54646 need to print
465465 need tp print 
654654 need to print
65465 need to print
23456 abcd
654654 asdfasfuoe

Now i need the lines between the patterns "abcd". Is there a way to achieve this using 'sed' or 'awk'?

Thanks in advance

Sridhar

ghostdog74 · 04-26-2009, 01:36 AM

Code:

# awk '$2=="abcd" && f{f=0;next} $2=="abcd"{ f=1;next}f' file
54646 need to print
465465 need tp print
654654 need to print
65465 need to print

Disillusionist · 04-26-2009, 02:29 AM

Nice code!

Took me a while to understand as I don't use awk that often

ksri07091983 · 04-26-2009, 03:21 AM

Hi ghostdog74

That was great!! Thanks a ton for the code.

Sridhar

ghostdog74 · 04-26-2009, 03:44 AM

one thing to take note is i only suggested the code based on the sample file. if there are more sets of abcd, then its a different story.

jlliagre · 04-26-2009, 06:14 AM

Here is something that uses sed instead of awk, probably easier to understand but requiring and additional command to filter out the pattern:

Code:

sed -n '/abcd/,/abcd/p' testfile | grep -v abcd