Variable doesn't work on a simple bash script

bmxakias · 07-30-2018, 02:02 PM

Hello

I am using this command:

Code:

awk '($9 ~ /307/)' /home/nginx/domains/mydomain.com/log/access.log | awk '{print $7}' | sort | uniq -c | sort -rn

and i am getting an output like this:

Code:

      7 /login/
      3 /login
      1 /login/?ref=a

Now i was trying to create a bash script for it like this:

Code:

#!/bin/bash

echo Please select the error code:
read errorcode

awk '($9 ~ /${errorcode}/)' /home/nginx/domains/mydomain.com/log/access.log | awk '{print $7}' | sort | uniq -c | sort -rn

as an error i am typing 307 but it doesn't work as i get a blank result

When i use echo and the variable it works...

I was trying to set also the variable in quotes but it was not working ....

Anyone knows how to do that?

Thank you

NevemTeve · 07-30-2018, 02:06 PM

Code:

awk '($9 ~ /'"$errorcode"'/)' filename

Turbocapitalist · 07-30-2018, 02:32 PM

The -v option in AWK brings an environment variable into the program:

Code:

#!/bin/bash

echo Please select the error code:
read errorcode

awk -v e=${errorcode} '$9 ~ e { print $7 }' /home/nginx/domains/mydomain.com/log/access.log \
        | sort | uniq -c | sort -k1,1rn

AWK variables are just plain strings and not preceded by a dollar sign.

See "man awk" for the details on the version of AWK you have.