To get a pattern of chessboard

som_kurian · 11-17-2007, 12:17 AM

Hi friends,

For getting a pattern of chessboard

But due to some reasons..I am not getting the desired output.Can u help me with this..

for (( i=1; i <= 9; i++ ))
do
for (( j=1; j <= 9; j++ ))
do

tot=`expr $i + $j`
tmp=`expr $tot % 2`
if [ $tmp -eq 0 ]/* if even puts white color */
then
echo -e -n "\033[40m"
else
echo -e -n "\033[47m"
fi
done
echo -e -n "\033[40m"
echo " "
done

juergen · 11-17-2007, 02:02 AM

You are getting pretty close, but:

You need to ditch the /* */ comment; comments in bash start with a #
In the first for statement, for (( i=1; 1 <= 9; i++ )), the 1 in '1 <= 9' has to be turned into an i
The <= comparisons in both for statements should be regular < if you want a true 8x8 board
You need to actually print something in order for the color to show up; so the 'echo -e -n "\033[47m"' turns into 'echo -e -n "\033[47m "' (note the added space)
The two echos between the 'done' statements appear superfluous to me

That's what I came up with off the top of my head; the list may not be complete, but it ought to help a bit.

Good luck!

homey · 11-17-2007, 05:45 AM

Here's an example that was kicking around here awhile back...

Code:

#!/bin/bash

clear
echo ""

for (( i = 1; i <= 8; i++ )); do
  for (( j = 2; j <= 9; j++ )); do
    tot=$(expr $i + $j)
    tmp=$(expr $tot % 2)
    if [ $tmp -eq 0 ]; then
      echo -en "\033[40m  "
    else
      echo -en "\033[47m  "
    fi
  done
 echo ""
done
echo -e "\033[0m\n"