This causes my program to crash/hang in C...

Scrag · 12-18-2004, 03:54 PM

This code casues my program to crash in C. Its compiles without any errors or warnings. Does anyone know why, or how I can fix this? The two lines of code will both cause program to hang/crash.

pathname = getenv("HTTPPATH");
strcpy(pathname, getenv("HTTPPATH"));

Code:

char pathname[1024];
.
.
.
if (!strcmp(httpGET_PATH, "")) {
		chdir(pathname);
		count = scandir(pathname, &files, 0, alphasort);
		setenv("HTTPPATH", pathname, 0);
	}
	else {
		pathname = getenv("HTTPPATH");  //CAUSES progrma to CRASH. 
                //strcpy(pathname, getenv("HTTPPATH"));  //Also causes to CRASH
		strcat(pathname, "/");
		strcat(pathname, httpGET_PATH);
		count = scandir(pathname, &files, 0, alphasort);
		chdir(pathname);
		setenv("HTTPPATH", pathname, 0);
	}

THANKS

bm17 · 12-18-2004, 04:53 PM

I don't know what C compiler you are using but it is sad that it doesn't issue a warning about assigning the results of getenv() to a char array. The second attempt (via strcpy()) is better, but you are not checking the return value of getenv(). It might be zero. I suggest that you call getenv("HTTPPATH") first, validate and printout the return value, and then strcpy it into pathname.