Shell variables in awk to define range

fur · 09-01-2007, 02:15 PM

I'm trying to use a shell variable in the following awk command.

Code:

awk  '/"domain.com"/,/^};/' named.conf

That will run properly, and output the zone data for domain.com.

What I want to do is replace "domain.com" with a shell variable that will have changing values.

I am having a problem with shell variables in this usage of awk. As a test I did this,

Code:

$ DOMAIN=example.com
$ awk -v zone=$DOMAIN 'BEGIN { print zone}'
example.com

Works fine, however when I try to use it with the initial awk command it doesn't work as expected.

Code:

awk -v domain=$ZONE '/domain/,/^};/' named.conf

Where $ZONE is equal to a valid zone in named.conf returns nothing. It is instead looking for the word "domain" and not the variable.

Thanks in advance

fur · 09-01-2007, 02:22 PM

Nevermind,

awk "/$ZONE/,/^};/" named.conf

awk -v domain="$ZONE" '$0 ~ domain, /^};/' named.conf

Both work.

EDIT:

Those will also match subdomains,

To fix that so they only return an exact match,

awk "/\"$ZONE\"/,/^};/" named.conf

or

awk -v domain="$ZONE" '$0 ~ "\""domain "\"", /^};/' named.conf