selecting only the required portion of string in a line

raghu123 · 09-17-2008, 01:30 AM

Hi all,
I have n files like this.....

rot-matrix-3bwr_c.pdb-4hmg_c.pdb.txt
rot-matrix-3ckz_a.pdb-5hmg_a.pdb.txt
rot-matrix-5hmg_c.pdb-5hmg_e.pdb.txt

I want a command for getting only 4hmg_c.pdb ; 5hmg_a.pdb ; 5hmg_e.pdb
(i.e the letters after the third "-" but before ".txt")
SO that i can put the code in loop for n entries......for sample I have just pasted 3 entries......

Plz help

chrism01 · 09-17-2008, 01:48 AM

Code:

echo rot-matrix-3bwr_c.pdb-4hmg_c.pdb.txt|cut -d'-' -f4|cut -d'.' -f1,2

4hmg_c.pdb

jschiwal · 09-17-2008, 01:51 AM

You could use sed and create a regular expression that matches the part you want to save.
sed -s 's/rot-matrix-...._.\.pdb-\(.*\).txt/\1/' testfile
4hmg_c.pdb
5hmg_a.pdb
5hmg_e.pdb

ghostdog74 · 09-17-2008, 02:11 AM

Code:

ls -1 rot* |while read line ; do a=${line##*-}; echo  ${a%.*}; done

raghu123 · 09-17-2008, 02:19 AM

Its working fine..........Thanq