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But since you mention records, this might be a task for Perl with the -a and -l options or just plain AWK. Please describe in a bit more detail what you aim to do.
Your capture groups are wrong, you must capture what you want to keep.
And .* is greedy; in -z mode it might span over the entire file till the last line.
Concatening lines can be done without -z
Code:
sed '/Online/{N;N;s/\r\n/ /g;}' test.txt
The N comand appends the next line to the input buffer, and the newline in between becomes a \n
And .* is greedy; in -z mode it might span over the entire file till the last line.
That's an important point I neglected to make: the ".*" will consume as much as possible (i.e. the entire rest of the file) before gradually backtracking (as little as possible) in order for the pattern to find a match.
In a multi-record file this will result in incorrect behaviour, because \1 will be most of the rest of the file and \2 may well be empty (if there's a trailing \r\n) otherwise it'd be the last line of the last record.
That's the reason for using "[^\r\n]*" instead of ".*" - in almost all cases when people write "." they really want "[^delimiter]" (some will use ".*?" which can work but is less efficient).
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