sed question about bash related

grail · 05-02-2010, 10:58 PM

Quote:

The bottom line is i am using the command to extract data twice.
In order to assign them to a different variables

Sorry I must be missing what you mean here

Why would you extract the same data twice??
I understand assigning to two different variables, but that would just be:

Code:

a=$data
b=$data

Quote:

they are on different columns after cleaning: column1 and column2, i was trying but i think it is not possible.

Here you mention two columns, maybe if you would give another example like the one on Post #4 so I can see what you mean.
As for "not possible", o ye of little faith. I may not be able to solve it, but I am sure someone can

patolfo · 05-03-2010, 09:49 AM

Code:

a non useful header
a non useful header
string
      stringsomething
            lots of ah
            lots of ah
                      meaningful data
            lots of ah
            lots of ah
                      stringsomething
meaningful data
--non useful tail
--non useful tail
and spaces and tabs of course for a finishing touch

After processing with:

Code:

lista=$(sed -n '/^'"$1"'/,$p' $2 | sed '/'"$1"'|ah|-/ d')

I got

Code:

meaningful data
meaningful data
meaningful data
meaningful data
meaningful data
meaningful data

A string and a scalar, the first column is a name, and the second is the data, a value.
Problem is i need both of them, not only one as i originally thought, so
i have to do this:

Code:

$name_of_socket=$(sed -n '/^'"$1"'/,$p' $2 | sed '/'"$1"'|ah|-/ d' | awk '{print $1}')
$socket_value=$(sed -n '/^'"$1"'/,$p' $2 | sed '/'"$1"'|ah|-/ d' | awk '{print $2}')

It is the same command, kind of repetitive

grail · 05-03-2010, 09:57 AM

Or:

Code:

name_of_socket=${lista[0]}
socket_value=${list[1]}

Note: Be carefule about placing $ at the fron of your variable assignments, it will not work as expected.