Hello all, I would like my C program.
I am using getopt, but it don't work as I would.
The program is:

....
....

main(int argc, char** argv) {

int c;
extern char* optarg;
extern int optind,opterr;

.....
.....

opterr = 0;

c = getopt(argc, argv, "ao");
switch (c) {
case 'a': printf(optarg);
break;
case 'o': printf(optarg);
break;
default: printf("opzione non valida");
break;
}

.....
.....
.....

I want use my program in this way:

#myprogram -a argument1 -o argument2

and I want that when

case 'a': then the program must print argument1

but it don't work!!

I want the same behaviour for -o option
How can I solve this problem?

Thanks everyone to help

You do not tell getopt the "a" and "o" options take arguments.

Pass the parameter to getopt instead of "ao".

Ok, it works, but it isn't yet perfect...
The code is the following:

opterr = 0;

while ((c = getopt(argc, argv, "a:")) != -1) {
switch (c) {
case 'a': printf(optarg);
break;
case 'o': printf(optarg);
break;
default: printf("opzione non valida");
break;
}
}

I try:

./myprogram -a argument1 -o argument2

and it print 'argument1' and 'argument2'

but I'd like can specify also more than one parameter in -a option, for example, I would use also this syntax:

./myprogram -a argument1 argument2 argument3 -o argument4

How can I solve this other problem?

Thank you in advance.

AFAIK, getopt doesn't support this way of passing parameters.