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Old 08-11-2006, 10:45 AM   #1
joelhop
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Registered: Mar 2004
Location: Pennsylvania::USA
Distribution: Fedora Core 6
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Question Php Coding Question


Hello All,

I am writing some php code where I have a string that I want to be evaluated by php. This is a very simplified example of what I am trying to do on a larger scale, I am just wondering if this is possible:


function getSomeNum()
{
return "23";
}

$funkvar = "getSomeNum()";

echo $funkvar;

Instead of it literally echoing the string: getSomeNum()

I would like it to echo the result of the actual function getSomeNum() or 23.

Is there a way to tell php to evaluate a string,like echo eval($funkvar) and have it give me the result of getSomeNum() which is 23 instead of the literal string "getSomeNum()"?

Some way to make: echo $funkvar and echo getSomeNum() both result in 23;

Instead of echo getSomeNum() = 23
and echo $funkvar = getSomeNum()

Thanks!
-Karl

Last edited by joelhop; 08-11-2006 at 10:49 AM.
 
Old 08-11-2006, 10:54 AM   #2
pnellesen
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Registered: Oct 2004
Location: Missouri, USA
Distribution: Slackware 12.2, Xubuntu 9.10
Posts: 371

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Did you try
Code:
$funkvar = getSomeNum();
without the double quotes?
 
Old 08-11-2006, 12:33 PM   #3
joelhop
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Registered: Mar 2004
Location: Pennsylvania::USA
Distribution: Fedora Core 6
Posts: 100

Original Poster
Rep: Reputation: 15
That solution will work if I wish to store the value of the result of getSomeNum() into $funkvar. I am looking to store the actual function name as a string getSomeNum() and then be able to have that string be evaluated later on.

I ended up solving the problem with this solution:

<?php

function getSomeNum()
{
return "23";
}


$funkvar = "return getSomeNum();";

echo eval($funkvar);

?>

Putting the return statement before the function name string, allows eval to evaluate that function and return the result.
 
  


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