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Old 03-21-2004, 12:28 PM   #1
raven
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Registered: Dec 2001
Location: Basel, Switzerland
Distribution: ubuntu
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perl regexp problem


hello

i have a question in perl

lets say for example that I have the string with substrings "/:" in it (multiple occurances are possible). Now I want to extract these and replace them with something else (let's say with "...") how can I do that? I tried: $var=~y/\/:/\n/s; but this replaces every "/" only, and thats not what I wanted...

Any idea?

Thanks

raven
 
Old 03-21-2004, 02:21 PM   #2
infamous41md
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Registered: Mar 2003
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Code:
[n00b@localho.outernet] cat test.pl
#!/usr/bin/perl


$var = 'bla foo /:';

$var =~ s#/:#a#g;

print "$var\n";
[n00b@localho.outernet] ./test.pl
bla foo a
im no perl whiz, but this seems to work.
 
Old 03-21-2004, 06:08 PM   #3
raven
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Location: Basel, Switzerland
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Posts: 297

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yes, it did work, thanks alot. where was this kinda stuff documented? I read trough a few doc, but did not find *this* one...

raven
 
Old 03-21-2004, 06:10 PM   #4
infamous41md
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well, i know u can use anything as teh separator of reg-ex's, but i think iread that in some deitel book a while go
 
Old 03-21-2004, 11:49 PM   #5
aluser
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Registered: Mar 2004
Location: Massachusetts
Distribution: Debian
Posts: 557

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Code:
perldoc perlrequick
perldoc perlretut
perldoc perlre
I got those from "perldoc perl"
 
  


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