Perl question

Palamides · 01-20-2005, 01:01 AM

does anyone know what the command is to print something out to the shell command line...
for example if i run a program and i want it to execute another program with certain arguments depending on the outcome of the program, once itś done running. Does anyone know what the code would look like to perform such a task if its evne possible? thanks

jkobrien · 01-20-2005, 04:49 AM

It sure is. The command "exec" will replace the current process (the perl script) with the shell and will run whatever command you put in it.

e.g. exec "ls -l $file_decided_on_by perl_script";

The command "system" does the same thing except it generates a new process.

John

jonaskoelker · 01-20-2005, 10:13 AM

see also http://sial.org/howto/perl/backticks/ and google("perl backtick") or google("perl backstick").

Palamides · 01-20-2005, 03:57 PM

thanks a lot!

Palamides · 01-20-2005, 09:50 PM

i have another question for example i have this code:

$x=0;

for($x=1000; $x<=9999; $x++)
{
exec "/usr/local/programToBeExecuted $x";
}

when i execute this, for some reason it only executes the 'exec "/usr/local/programToBeExecuted $x";' once so itd be like #program 1000 in the command line.
then it stops

anyone know why?

dustu76 · 01-21-2005, 12:35 AM

Just read the post by jkobrien. He made the reason amply clear.

This is not a repair shop. Read & understand the posts.

Palamides · 01-21-2005, 01:09 AM

my bad missed the "system" part, thanks a lot it worked perfectly