pattern match : korn shell

tostay2003 · 12-31-2008, 10:21 AM

Hi all,

I have small comparison to make.

I have say two strings,

Code:

StringA="abcdefg"
StringB="abc"

I would like to have a statement which checks if the string contains the below pattern.

Code:

"a _ _ d _ f _"

StringA passes the test, where as StringB fails the test

How can I make such comparison, without using grep or sed.

makyo · 12-31-2008, 12:08 PM

Hi.

One way:

Code:

#!/usr/bin/env ksh

# @(#) s1       Demonstrate globbing [file-like] pattern matching.

echo
export LC_ALL=C
echo "Environment: LC_ALL = $LC_ALL"
echo "(Versions displayed with local utility \"version\")"
version >/dev/null 2>&1 && version "=o" $(_eat $0 $1)
echo

for s in abcdef abc
do
  if [[ "$s" = a??d?f ]]
  then
    echo " String :$s: passes"
  else
    echo " FAILED to match :$s:"
  fi
done

exit 0

Producing:

Code:

% ./s1

Environment: LC_ALL = C
(Versions displayed with local utility "version")
Linux 2.6.11-x1
PD KSH v5.2.14 99/07/13.2

 String :abcdef: passes
 FAILED to match :abc:

Best wishes ... cheers, makyo