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Old 02-12-2005, 10:25 AM   #1
prx
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Registered: Feb 2005
Location: Boulder County, Colorado
Distribution: Centos5,6,7(production)/OSX(dev/personal laptop)
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odd recursion: calling "by hand" vs calling by cronscript...


I have a cronscript which checks (then fixes) users directories for badly named files - meaning I don't want to allow spaces or ampersands in file or directory names & it will replace spaces with underscores and removes ampersands.

If I have a directory uploaded by a user like this:

/var/pub/ftp/username/top level/second level/third level/
/var/pub/ftp/username/top level/second level/third level/pork & beans


then I call this script by typing it's name (I call it sr) in a bash shell like this:

cd /var/pub/ftp
sr

then I end up with:
/var/pub/ftp/username/top_level/second_level/third_level/ /var/pub/ftp/username/top_level/second_level/third_level/pork_beans

the program works by parsing directories then recursively calling itself to descend further until it has fix all files and directories below the directory it has been called.

I set it to run in a cronscript, and get different results! Here is what I get when it is called by cron:
/var/pub/ftp/username/top_level/second_level/third level/
/var/pub/ftp/username/top_level/second_level/third level/pork & beans

so, it doesn't successfully call itself when started by cron.

Here is the script for sr (called that originally for space replace)
and if you can give me a hint why this might be happening, I would be very grateful.

I just don't get why the recursion works when typed into bash, but not when called by cron

Running FC2, btw.
The cronjob belongs to root.

----

for i in *
do
if [ -d "$i" ] # if * is a directory
then
cd "$i" # descend into the directory
for y in *
do
tempa=$(echo $y | sed 's/ /_/g' | sed -e 's/\&//g' | sed 's/__/_/g')
wait
if [ "$y" != "$tempa" ]
then
mv "$y" "$tempa"
wait
fi
if [ -d "$tempa" ] # if this is also a directory, call this program
then
cd "$tempa"
sr # this is the name of THIS program, must be in your PATH
wait
cd ..
fi
done
cd ..
fi
tempa=$(echo $i | sed 's/ /_/g' | sed -e 's/\&//g' | sed 's/__/_/g')
wait
if [ "$i" != "$tempa" ]
then
mv "$i" "$tempa"
wait
fi
done

Thanks for you help,

Paul in Colorado

Last edited by prx; 02-12-2005 at 10:28 AM.
 
Old 02-12-2005, 11:48 AM   #2
jailbait
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Registered: Feb 2003
Location: Virginia, USA
Distribution: Debian 12
Posts: 8,337

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"I just don't get why the recursion works when typed into bash, but not when called by cron"

Cron jobs run with a skimpy PATH. You might have the case where sr is on the bash PATH but not on the cron PATH. If that is the problem then you can fix it either by setting the PATH in sr or by invoking sr using the full path name.

Also I do not think that your script includes the logic for the case where sr changes a file name to an already existing file name.

---------------------------
Steve Stites
 
Old 02-12-2005, 02:14 PM   #3
prx
LQ Newbie
 
Registered: Feb 2005
Location: Boulder County, Colorado
Distribution: Centos5,6,7(production)/OSX(dev/personal laptop)
Posts: 11

Original Poster
Rep: Reputation: 0
Thanks so much! That did the trick!

-Paul
 
Old 02-12-2005, 02:19 PM   #4
prx
LQ Newbie
 
Registered: Feb 2005
Location: Boulder County, Colorado
Distribution: Centos5,6,7(production)/OSX(dev/personal laptop)
Posts: 11

Original Poster
Rep: Reputation: 0
also, while we are on the subject....

Is there an easy way to import the bash PATH to the cron PATH at the beginning of a cron script?
 
Old 02-12-2005, 04:59 PM   #5
jailbait
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Registered: Feb 2003
Location: Virginia, USA
Distribution: Debian 12
Posts: 8,337

Rep: Reputation: 548Reputation: 548Reputation: 548Reputation: 548Reputation: 548Reputation: 548
"Is there an easy way to import the bash PATH to the cron PATH at the beginning of a cron script?"

There is a place in the crontab entry where you name the command you wish to run. You can make this entry a series of commands separated by semi colons ;. Set the PATH and then invoke sr.

If you mean can you use the same PATH as set by root bash the answer is "I don't know". Cron runs as its own daemon. It is not the user root although cron runs as ID 0. Finding out what PATH the user root uses and setting that PATH in the cron daemon is probably more trouble than it is worth. Anyway, I don't know how to do it off the top of my head.

---------------------------
Steve Stites

Last edited by jailbait; 02-12-2005 at 05:05 PM.
 
  


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