number of element in a array of pointer?

os2 · 03-04-2005, 02:29 PM

hi

under linux, c language

Code:

char *fname[]={"/A_L1_HLD_YEL_NOR_Run_Counter.txt", "/A_L1_HLD_GRN_NOR_Run_Counter.txt", "/A_L2_HLD_GRN_NOR_Run_Counter.txt", "/B_L1_HLD_YEL_NOR_Run_Counter.txt", "/B_L1_HLD_GRN_NOR_Run_Counter.txt", "/B_L2_HLD_GRN_NOR_Run_Counter.txt", "/C_L1_HLD_YEL_NOR_Run_Counter.txt", "/C_L1_HLD_GRN_NOR_Run_Counter.txt", "/C_L2_HLD_GRN_NOR_Run_Counter.txt" };

int i;
        for(i=0; i < SIZEOFFNAME;i++){

for each element in fname (SIZEOFFNAME)... i would like to do something...

how to get the number of elment for fname?

perfect_circle · 03-04-2005, 02:38 PM

what do you mean by element? fname is just an array of pointers with 9 entries(pointers).

itsme86 · 03-04-2005, 02:47 PM

You can do it like argv works. Just end the entires with a NULL:

Code:

{
  char *strings[] = { "foo", "bar", "baz", NULL };
  int i;

  for(i = 0;strings[i];++i)
    puts(strings[i]);
}

os2 · 03-04-2005, 02:47 PM

Quote:

Originally posted by perfect_circle
what do you mean by element? fname is just an array of pointers with 9 entries(pointers).

in my for loop, i would like to go on the 1 entries, after second entries...

i don't know if *fname[i] is ok?

are there any place we could post c program and people comment it?

i would like to improve a c program, but i'm not a c expert

perfect_circle · 03-04-2005, 02:53 PM

I think itsme86 already answered you that. An array of pointers is just an array.

aditya1 · 03-08-2005, 08:35 PM

try this:
int i=0,count=0;
while(*fname[i]!=NULL)
{
count++;
i++;
}

Matir · 03-08-2005, 09:21 PM

Quote:

Originally posted by aditya1
try this:
int i=0,count=0;
while(*fname[i]!=NULL)
{
count++;
i++;
}

Why not just?

Code:

int count=0;
while(fname[count])
count++;

aditya1 · 03-09-2005, 11:50 AM

thanks for ur suggestion