Need Grep command for the following output

minil · 12-29-2005, 06:29 AM

Hi
i need grep command for the following output.
I have a file. as given below

Code:

#192.168.48.155
10.0.0.4
       #11.0.0.1

#239.0.01
       #12.1.0.1
        192.168.48.172
192.168.48.100

#192.158.32.0

Questions as follows

To print lines which starts with # character.(# as first character .No space shoule be there #character). Output should be(Idont want blank lines.
Code:
```
#192.168.48.155
#239.0.01
#192.158.32.0
```
To print lines which with # character as first character in line and also line with any number of space followed by #character. output should be.
Code:
```
#192.168.48.155
      #11.0.0.1
#239.0.01
       #12.1.0.1
#192.158.32.0
```
To print lines which starts only with space character followed by # as first . Output should be as follows
Code:
```
     #11.0.0.1
     #12.1.0.1
```
To print lines which contains space followed by any characters
Code:
```
      #11.0.0.1
      192.168.48.172
      #12.1.0.1
```

Its urgent..
Thanks in advance.

druuna · 12-29-2005, 06:49 AM

Quote:

Originally Posted by minil

Questions as follows[list][*] To print lines which starts with # character.(# as first character .No space shoule be there #character). Output should be(Idont want blank lines.

Code:

#192.168.48.155
#239.0.01
#192.158.32.0

grep "^#" <infile>

Quote:

[*]To print lines which with # character as first character in line and also line with any number of space followed by #character. output should be.

Code:

#192.168.48.155
      #11.0.0.1
#239.0.01
       #12.1.0.1
#192.158.32.0

grep "^[ ]*#" <infile> (between the square brackets are a space and a tab)

Quote:

[*]To print lines which starts only with space character followed by # as first . Output should be as follows

Code:

     #11.0.0.1
     #12.1.0.1

grep "^[ ][ ]*#" <infile> (again, space and tab between the square brackets)

Quote:

[*]To print lines which contains space followed by any characters

Code:

      #11.0.0.1
      192.168.48.172
      #12.1.0.1

grep "^[ ][ ]*" <infile> (again, space and tab between the square brackets)

Hope this helps.

minil · 12-29-2005, 07:49 AM

Thank you very much druuna