Dear All,
Getting error
./Outline.sh: line 30: line: command not found

code:
while str="`line`"; do
echo $str
done < Outline.txt

"while linestr="`line`"; do" is the line number 30.

I am executing the shell script as follows
$Outline.sh

Any idea why the command not found error is coming.

Thanks and Regards
Pramod

Hi Pramod,
I script is working fine. Just check whether the line command is available on your machine.
-Cheers
indiajoe

Thanks for replying.
I checked the command line in My OS. It is not available in Linux.
$which line
[ismp_app@ysmp101 ~]$ which line
/usr/bin/which: no line in (/usr/lib64/qt-3.3/bin:/usr/kerberos/bin:/usr/local/weblogic/jrockit310_160/bin:/usr/local/bin:/bin:/usr/bin

Any idea .. how to configure line command in RHEL-5.


Thanks and Regards
Pramod

From the man page:
So--first try to find it with your package manager---otherwise download it.

But, what wrong with the "read" command? (I haven't had enough coffee to understand how "line" is differnet."

Moved: This thread is more suitable in <Programming> and has been moved accordingly to help your thread/question get the exposure it deserves.

Thanks for the reply.
I checked the differences between line and read command.
I used read command to read the line from file.
From this line i need to create a file which is used for awk.

Code :
while read linestr; do
param1=`echo $linestr | sed -e 's/^\(.*\)\;\(.*\)\|\(.*\)$/\1/'`
param2=`echo $linestr | sed -e 's/^\(.*\)\;\(.*\)\|\(.*\)$/\2/'`
param3=`echo $linestr | sed -e 's/^\(.*\)\;\(.*\)\|\(.*\)$/\3/'`
echo '/'$param2'/{printf("'$param3' at %s\\n", substr($0,0,20))}' >> temp.sed
done < input.txt


The file input.txt looks like this
manager;2909,Order_MAIL : Invalid Mail Address|!manager,ERROR,Notice_MAIL:Invalid Mail Address found.
manager;ORA-2023|!manager,ERROR,ORA-04031 Occured.
manager; : Delete failed|!manager,ERROR,DatabaseGarbageCollect : Fail delete user id
MakeAllMailList;ORA-|!MakeAllMailList,ERROR,MakeAllMailList:Fail make AllMailList
Set;ORA-|!PlanSet,ERROR,PlanSet:Fail AccountSignupPlan PlanSet


Here i am getting proper values for param1 and param2. However i am getting empty for param3.

I am not able to find why i am not getting param3.
I did googling found the website
http://www.grymoire.com/Unix/Sed.html
but not able crack.

Please help.


Thanks and Regards
Pramod

the way you are doing it is so messy. If you want to pass things to awk, you might as well learn and get know how to use awk, because the above can be done in one awk script nicely and easily. Show how your output looks like in the end, ie what you want to get from the input file.

The sed statements create a file in /tmp directory.
It contents are as follows
/2909,Notice_MAIL : Invalid Mail Address|!manager,ERROR,Notice_MAIL:Invalid Mail Address found./{printf(" at %s\\n", substr($0,0,20))}

I wanted to get the content as
The sed statements create a file in /tmp directory.
It contents are as follows
/30034,Notice_MAIL : Invalid Mail Address|!manager,ERROR,Notice_MAIL:Invalid Mail Address found./{printf("Notice_MAIL:Invalid Mail Address found. at %s\\n", substr($0,0,20))}


The text written in block is not getting populated from the text file.

I am not sure what you want to do.

If you have lines of the format "string1;string2|string3" and you want to print "<string3> at <first 20 chars of string2>" it can be done like thisIs there any particular reason why you are using /bin/sh rather than /bin/bash?

Can you tell me what the following code will do.
code

Please give me the example.

I am not able to understand the code.