Include source problem with sh

elmu · 06-19-2007, 07:36 AM

Hello,

I have problems with including shell script inside an other script. I have 2 files - see below - where I try to use a varible in file 1 which was defined in file 2. It works fine with ksh but now I have to write it in bourn shell and it doesn't work.

Any idea?

File 1: (test.sh)

Code:

#!/bin/sh
echo "Test started source the other file"
./intern.sh
echo "Test is ${TEST}"

File 2: (intern.sh)

Code:

#!/bin/sh
TEST=/tmp
export TEST

trashbird1240 · 06-19-2007, 07:52 AM

Hi,

My main experience is with zsh; it looks like your included script is executed inside a new shell, in which case the variables will not carry over. You may be able to pass them as arguments to the new shell.

HTH

Joel

jlliagre · 06-19-2007, 07:52 AM

You need to source the intern.sh script, not execute it in a subshell as you did.

Code:

. ./intern.sh

gnashley · 06-19-2007, 11:56 AM

Or this:

source ./intern.sh

cfaj · 06-19-2007, 02:05 PM

Quote:

Originally Posted by gnashley

Or this:

source ./intern.sh

There is no source command in most shells; it is limited to csh (which is not recommended for scripting) and bash.

The standard command to source a script (i.e., execute it in the current shell) is dot, e.g.:
Code:
. /path/to/script

trashbird1240 · 06-20-2007, 08:53 AM

Quote:

Originally Posted by cfaj

[INDENT]
There is no source command in most shells; it is limited to csh (which is not recommended for scripting) and bash.

The cool thing about the Z Shell is that it is most shells. And it does include a "source" command

If Z Shell is unavailable, I understand; if you have the means, I highly recommend picking it up.

Joel