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Old 06-25-2009, 11:05 AM   #1
desb01
LQ Newbie
 
Registered: Jun 2009
Posts: 2

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How to pass the result of a command to another command (like grep)


Hi,

I would like to pass the following command result to another command :

Code:
$ grep -ri 30855 *.xml | cut -d ':' -f 1
0672.xml
0674.xml
0675.xml
0678.xml
0679.xml
0681.xml
0682.xml

So I would like to grep the word name in each of those file.

I tried
Code:
grep -ri 30855 *.xml | cut -d ':' -f 1 | grep name
without any success.

What do I do wrong ?

Thank you.
 
Old 06-25-2009, 11:29 AM   #2
irey
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Registered: Jun 2008
Location: Torino, Italy
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I'm not sure I understood your intentions, but if you're trying to use the output of the first command as a list of files for the second grep, then you should include the list of files in the command line, not pipe it into grep.

Code:
grep name `grep -ri 30855 *.xml | cut -d ':' -f 1`
Note that this example uses a backward apostrophe (ascii code 96).
 
Old 06-25-2009, 11:36 AM   #3
Hko
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Registered: Aug 2002
Location: Groningen, The Netherlands
Distribution: Debian
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Or this alternative:
Code:
grep -ri 30855 *.xml | cut -d ':' -f 1 | xargs grep name
 
Old 06-25-2009, 11:42 AM   #4
Trumpen
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Registered: Dec 2008
Location: Italy
Distribution: Debian & Ubuntu
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Here is a slightly different way to solve the problem:

Code:
grep -ri "30855\|name" *.xml | cut -d: -f1 | uniq -d
This way we read the files only once and in addition we avoid the problem with filenames containing white spaces.
 
Old 06-25-2009, 12:09 PM   #5
desb01
LQ Newbie
 
Registered: Jun 2009
Posts: 2

Original Poster
Rep: Reputation: 0
Thank you all.

irey and Hko got it right, this is what I was trying to do.

Trupen, I don't know why but your solution didn't work.
 
  


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