Hi Friends,

I am writing a script where I need to grep out number of lines, which are not fixed in numbers but starting and end lines of that para are constant.

e.g

Please block below URLs
http://...........
http:...........
234.87.98.30
.
.
.
.
.

End of Urls

any one has any idea how can I filter out those URLs or number of lines between "please block" and "end"

show a better example, and describe and show clearly what you want as output.

Well, I would like filter out the lines which keeps on varying so i can not use -A or -B syntax with grep.
so looking for other better option by which I can grep out those lines. The one clue I can see is since these lines always starts and ends with certain fixed lines, I could use that criteria to extract the lines?

say for example

# Para Starts from below
Please block below URLS.
http://abc.com
123.23.24.45
http://xyz.com/aere.php
.
.
.
.
.
.

end

# para ends

So in the above example if I could filter out the lines between "Please block" and "end" I guess I could achieve the goal but not sure how to extract the same with the help of grep.

Do let me know if you have any other solution.

http://www.ibm.com/developerworks/li...GX03&S_CMP=EDU -> see "Listing 3: Printing a range of lines".

Would it be possible to achieve the same in Bash Script?
Please let me know if you find any alternative.

First you asked for grep, now you want bash ??? How about sed

Using awk, if a line begins with Please block below URLs set a flag.

If the flag is set, then write subsequent lines to another file

If a line begins with End of Urls then unset the flag.

End