Dear Sir,
i want know how to change char or string into unsigned short.
Actualy i want to store a string into 2 bytes data type variable of pointer.
Like unsigned short s[]={'H','e','l','l','o',0};
it will work

but if i want to store a string into unsigned short or into 2 bytes data type ....
then what i should do???

Thanks
Krishna

No need for formalities, we're all equal here.

char is a 1 byte value (usually). so in theory you can put two bytes into one unsigned short.

if char[0]=, for example, 67, and char[1]=68, then try

unsigned short int x = 256*char[0]+char[1]. Should work.

Important: you must use a single character or a single character array for this to work (char something[]). Don't use char *something[], cause thats a \n (newline, char 10) termintated string, not a character that can be represented by a single ascii byte.

But i want to store a string into unsigned short
Like:
char *ch="hello";
I want to store the value of ch into a unsigned short.

Like: unsigned short sh or *sh;
how can i operate it that the value of sh should be "hello";

Thanks
Krishna

Hi,

If I understand you properly then I'd have to say that you can't achieve what you want to do. The reason being that you are trying to fit too much into the space allocated.

If you consider a variable like a suitcase, and data represents the cloths you want to store, you can only fit so many cloths into the suitcase, you might be able to cram a little more in but there comes a point when it's just not possible to add any more and you need to go out and get some more suitcases. In you example each char is designed to hold one character, so trying to hold more is going to lead to problems (you can fit a few more in with compression but there are limits which you will reach very quickly)

However, if you could expand on what it is you are trying to achieve then we might be able to help you.

graeme.

What language is it, C or C++? In C it will be a little bit harder to achieve; you have to convert it by hand like "ichrispa" already suggested. In C++ you have a new data type named 'wchar_t' which is two bytes long and made for holding wide characters. To assign a wide string to such a type may look like this:
Important: Don't forget the 'L' before a string; this indicates a wide string (16-bit chars)!

Im using C++ & linux
But Flesym, size of wchar_t 4 bytes in linux. i want to store it in 2 bytes storage's variale.

Thanks

No, size of wchar_t is 2 bytes. Try this:
In the output, you will see that it is "2".

I guess you checked the size of "wchar_t *"? -A pointer is of course 4 bytes as long as you have a 32-bit address space.

<EDIT>
Oh, I just tried it under Linux and you are right, it is indeed 4 bytes..., mmmh, i'll check it out
</EDIT>

Ok, wchar_t is very platform dependent (am I the only one who thinks this is stupid??) However, most compilers provide an option to change the size of this type. If you are using g++, compile with '-fshort-wchar'. Example:
This will change the size to 16 bit.

Hope that helped
-flesym

I'm obviously not understanding this thread because I don't know why the wchar data type is being introduced. The purpose of wchar is to support UNICODE characters which require more than one byte to be represented.

So going to the original question what is it you are trying to achieve by storing a string in a unsigned short? What do you intend to do with this unsigned short once you have squeezed the data into it?

Yes, I think that is exactly what "krishnacins" wants to do (please correct me if I'm wrong): A string with 16-bit characters. I thought a UNICODE-character was 16bit and platform indepandent, but it is not; sometimes it is 16 bit and sometimes 32 bit. But as I said before, g++ can switch wchar_t to be the desired 16 bit (like unsigned short int). Although this option has to be used with care: See "man g++" for details.

There are different versions of Unicode, utf8 is probably the most common encoding and will vary from 1 to 4 bytes depending upon the script used - so the latin script is typically 1 byte whilst variants of the chinese script will require four bytes to represent it.

The difference between "ASCII" and "UTF-8"; between "char *" and "wide characters" and "multibyte characters" etc can be VERY confusing; internationalization support can be VERY inconsistent from platform to platform, compiler to compiler, and library to library.

Here's a great article that might help:

PS:
As Flesym said, if you want a Unicode string constant, then the "L" modifier is the way to do it:If you want to insure wchar_t is 16 bits, then is arguably the best way to do it (at least with gcc/g++).

Hello,
i want to convert a string (str) into wchar_t (wch) & i want that g++ compiler wiil change the size of wchar_t varieble from 32 bts into 16 bits.So im using as g++ -fshort-wchar file name. Its working if im using
as wchar * wch =L"Hello";

but im using below function who takes one string variable & return wchar pointer.

wchar_t * New_mbstowcs ( string str)
{
char *string = (char *) str.c_str();

size_t size = strlen (string) + 1;

wchar_t *buf = new wchar_t() ;

size = mbstowcs (buf, string, size);

if (size == (size_t) -1)
return NULL;
return buf;
}


It returns wchar_t variable or pointer which has 32 bits size.
& g++ -fshort-wchar this commond doesnt change the size of wchar from 32 bits to 16 bits. coz i think im unsig STL function c_str();

So please can anybody help me to come out from this prob that how can i use wchar_t varible of 16 bites.... with using above function

thanks I have done it

Hello Krishnacins,
I need to know the solution, please because I have the same problem. Can you tell me this? thanks